Question
A trader buys two articles A and B. The cost price of A
is (200 + 10x) rupees and the cost price of B is (150 + 5x) rupees. If he sells each of them at a profit of 20% in the first situation, and sells each of them at a loss of 10% in the second situation, then the difference between the total selling prices in the first and the second situations is Rs. 195. What is the cost price of article A?Solution
ATQ, Let CP_A = 200 + 10x Let CP_B = 150 + 5x Total cost price = CP_A + CP_B = 350 + 15x First situation (20% profit on each): Total SP₁ = 1.20 × (CP_A + CP_B) = 1.20(350 + 15x) Second situation (10% loss on each): Total SP₂ = 0.90 × (CP_A + CP_B) = 0.90(350 + 15x) Given difference: SP₁ − SP₂ = 195 1.20(350 + 15x) − 0.90(350 + 15x) = 195 (1.20 − 0.90)(350 + 15x) = 195 0.30(350 + 15x) = 195 350 + 15x = 195 / 0.30 = 195 × (10/3) = 650 15x = 650 − 350 = 300 x = 20 So CP_A = 200 + 10x = 200 + 200 = 400
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