Question
The selling price, cost price and marked price of a bag are
in the ratio 7:5:10. If the profit is Rs. 800, calculate the discount allowed on the marked price.Solution
ATQ,
Let the selling price, cost price and marked price be Rs. 7x, Rs. 5x and Rs. 10x respectively
According to the question,
Profit earned = 7x – 5x = Rs. 2x
Therefore, 2x = 800
Or, x = 400
Therefore, discount offered = 10x – 7x = 3x = 3 × 400 = Rs. 1200
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
l). 3p + 2q = 27
ll). 4p - 3q = 2
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
Find the maximum value of f(x)= –2x² +8x + 3.
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...
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