Question
A shopkeeper cheats his customer by using faulty weight and
earns profit percent of 12% after selling. How much less the shopkeeper will sell when the customer wants to purchase 5.04 kg?Solution
Let price of 1 kg = 1000
Let he sell 'x' grams at cost of 1 kg.
SP of 'x' grams = 1000
SP of 1 kg = (1000/x) * 1000 = (1000000/x)
Profit amount = (1000000/x) - 1000
Profit percent = [(1000000/x) - 1000]/1000 * 100 = 12
(1000/x) - 1 = 0.12
1000/x = 1 + 0.12 = 1.12
x = 1000/1.12
Amount given at the purchase of 5.04 kg = (1000/1.12) * 5.04 = 4500 grams
Less amount given = 5040 - 4500 = 540 grams
Statements: B ≤ C < E; B ≥ G < H; G > I ≥ L
Conclusions:
I. G ≤ C
II. H ≥ L
III. G > E
Statement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E II. H > K
Statement: C < P > T = E < R; G > R > A < D
Conclusions:
I. T < G
II. G ≥ P
III. T > A
Statements: D = E ≥ F; G > H > D; D > J = I = K
Conclusions:
I. K > D
II. F < G
III. K < H
Statements: P % Q, P $ R, Q # S, R @ T
Conclusions:
I. R $ Q
II. S & T �...
Which of the following expressions will be true if the given expression ′S > T ≥ U < V < W′ is definitely true?
Statements: O @ G % N & A @ I % P; V $ U & Q # A
Conclusions:
I. N @ U
II. G % V
III. V # I
Statement: J > K ≥ C = D ≤ Y < Z
Conclusions:
I. Z > C
II. J ≥ Y
III. J > D
IV. C > Z
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Which one the following symbols should replace the question mark in the given expression, in order to make the expressions L ≤ I as well as N > K ...