Question
A trader purchased two articles for a combined cost of
₹6400. He sold the first article at a profit of 30% and the second article at a loss of 20%. The total selling price of both articles was ₹7100. Determine the cost price of the first article.Solution
Let the cost price of the first article be ₹x. Then, the cost price of the second article = ₹6400 - ₹x. Selling price of the first article = ₹x + 30% of ₹x = 1.3x. Selling price of the second article = (₹6400 - ₹x) - 20% of (₹6400 - ₹x) = 0.8(₹6400 - ₹x). Total selling price = 1.3x + 0.8(₹6400 - ₹x) = ₹7100. Simplifying, we get: 1.3x + 5120 - 0.8x = 7100 0.5x = 1980 x = ₹3960. Correct answer: c) ₹3960
9, 21, 67, 273, 1371, ?
85 135 172 ? 215 225
19, 37, 65, 91, 127, 169
Complete the series: 5, 20, 24, 6, 2, 8,?
91 93 97 100 ? 113
127 470 254 ? 315 342
...23 27 54 ? 195 231
...? + (55)2 = (140)2 – (80)2 – 6278
13 24 75 134 447 892
...D irection: Which of the following will replace ‘?’ in the following series
9, ‘?’, 1242, 1581, 1783
...
