Question
A person buys a piece of machinery for ₹60,000. After
1 year, he sells it at a 15% profit and reinvests the entire amount in a new machine. The second machine appreciates by 20% over 2 years. He then sells the second machine and makes a profit of ₹10,000 on the total investment. What was the selling price of the second machine?Solution
Initial investment = ₹60,000. First sale after 1 year: Profit = ₹60,000 × 15% = ₹9,000. Selling price = ₹60,000 + ₹9,000 = ₹69,000. Reinvestment in second machine = ₹69,000. Appreciation after 2 years: Appreciation = ₹69,000 × 20% = ₹13,800. New value after 2 years = ₹69,000 + ₹13,800 = ₹82,800. Profit from second sale = ₹82,800 - ₹60,000 = ₹22,800. Amount after selling second machine = ₹82,800. Profit made = ₹10,000 on total investment. Thus, the selling price of the second machine is ₹82,800. Closest option: b) ₹82,800.
Which of the following stages of black rust are found on alternate host?
Who developed the Training and Visit (T and V) system for agricultural extension services ?
The available water retained in soil is between_?
The most effective insecticide to control termite is ______
The early maturing variety of potato is:
International Food Safety standards are developed by
According to the law of demand
Extension education was first time started in which country?
The total outlay on commodity remains constant, even when there is a change in price, this occurs in case of:
Whorled type of antenna is found in:
Relevant for Exams:
