Question
A person buys a piece of machinery for ₹60,000. After
1 year, he sells it at a 15% profit and reinvests the entire amount in a new machine. The second machine appreciates by 20% over 2 years. He then sells the second machine and makes a profit of ₹10,000 on the total investment. What was the selling price of the second machine?Solution
Initial investment = ₹60,000. First sale after 1 year: Profit = ₹60,000 × 15% = ₹9,000. Selling price = ₹60,000 + ₹9,000 = ₹69,000. Reinvestment in second machine = ₹69,000. Appreciation after 2 years: Appreciation = ₹69,000 × 20% = ₹13,800. New value after 2 years = ₹69,000 + ₹13,800 = ₹82,800. Profit from second sale = ₹82,800 - ₹60,000 = ₹22,800. Amount after selling second machine = ₹82,800. Profit made = ₹10,000 on total investment. Thus, the selling price of the second machine is ₹82,800. Closest option: b) ₹82,800.
Which of the following box is kept just above the box L?
How many floors are in between L and R?
How many cartons are kept between T and S?
The Sales Tax officers work in which of the following cities?
How many chocolates are there in the box with Snickers?
Who among the following person stands third to the right of N?
Who among the following lives exactly between the floors on which Pranav and Sohan live respectively?
Who among the following has ordered from Snapdeal?
Who among the following belong to the Sales department?
Which of the following is true?
Relevant for Exams:
