Question
Article A is sold at a loss of 33.33% of its selling
price, and Article B is sold at a profit of 40% of its cost price. Both articles are sold for the same price. Given that there is an overall loss of Rs. 250, find the difference in the cost price of the two articles.Solution
Article A sold at 33.33% loss of SP, So CP of A – SP of A = 1/3 of (SP of A) So for article A, CP: SP = 4:3 Similarly for article B, CP: SP = 5:7 Selling price of A and B is same So CP: SP for A = 28: 21 CP: SP for B = 15: 21 There is an overall loss of Rs. 250 So (28 + 15) units – (21 + 21) units = 250 1 unit = 250 Required difference = (28 – 15) units x 250 = 13 x 250 = Rs. 3250 Hence answer is option C
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
540240 ÷ 24 ÷ 25 =?
17.5% of 400 – 24% of 150 = ?
(-251 × 21 × -12) ÷ ? = 158.13
√(?) = (897 × 51) ÷ 1016.6
[∛(3375/19683  )- ∛(125/1728  )  ] ÷ ∛(64/729)  = ? - 3/8Â
?% of 120 × 3√343 = 42 × 20
What will come in the place of question mark (?) in the given expression?
? × 18 + 3072 ÷ 24 = 20% of 1900Â
Simplify the given expression:
[(2.3)3 + (15.9) ³ + (3.7) ³ – 3 × 2.3 × 15.9 x 3.7)] / [(2.3) ² + (15.9) ² + (3.7) ² – 2.3 ...