Question
A shopkeeper sold an article after offering two
successive discounts of 20% and 22%, respectively. The marked price of the article is Rs. 2400. If the cost price of the article is 2000, then find the profit/loss percentage in the whole transaction.Solution
Marked price of the article = Rs. 2400 Selling price of the article = 2400 × 0.8 × 0.78 = Rs. 1497.6 Cost price of the article = Rs. 1497.6 So, loss percentage = [(2000 – 1497.6)/2000] × 100 = 25.12%
If X = 15°, find the value of:
sin²(4X) + cos²(3X) - tan²(2X)What is the value of [(tan 5θ + tan 3θ)/4 cos 4θ (tan 5θ – tan 3θ)]?
The minimum value of 9 cos2 θ + 36 sec2 θ isÂ
If tanθ – cotθ = a and cosθ + sinθ = b, then (b2 –1)(a2 + 4) = ?
Find the value of the given expression.
3 × (sin 30° + cos 60°)
- Calculate the value of sin120 o  + cos180 o  + tan225 o .
Solve the following trigonometric expression:

- If sin 2a = (3/2), then find the value of (sin a + cos a).
- Find the simplified value of the expression:sin 2 45 o  + sin 2 60 o  - (1/3) X tan 2 60 o
What is the simplified value of the given expression?
3(sin² 30° + sin² 60°) + 6sin 45° - (3sec 60° + cot 45°)