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ATQ, For P: Cost price of item = Rs. x Marked price = 1.60 × x = Rs. 1.6x Selling price of item = Rs. (1.6x – 120) For Q; Cost price of item = Rs. (1.6x – 120) Marked price = 1.25 × (1.6x – 120) = Rs. (2x – 150) Selling price of item = 0.90 × (2x – 150) = Rs. (1.8x – 135) According to question: 1.8x – 135 – 1.6x + 120 = 135 Or, 0.2x = 150 Or, x = 750 Profit earned by 'P' = 1.6x – 120 – x = Rs. (0.6x – 120) = 0.6 × 750 – 120 = Rs.330
If the side of an equilateral triangle is 12cm, then find the area (in cm 2 ) of the triangle (correct to two decimal places).
The angles of a triangle are in the ratio 4:5:3. Determine the sum of the smallest and largest angles of the triangle.
What is the height of an equilateral triangle with a side length of 14√7 cm?
In the given figure, AB ∥ QP, AB = x, PQ = x + 10, RB = x/2, BP = x + 1. Find PQ.
What is the length of the hypotenuse in an isosceles right-angled triangle if one of its equal sides measures 5√3 cm?
In a ∆ABC, angle BAC = 90°. If BC = 25 cm, then what is the length of the median AD?
