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ATQ, Let the cost price be Rs. 100 Selling price = Rs. 100 + 100 × 180% = Rs. 280 After increment, Cost price = 100 × 112% = Rs. 112 Selling price = Rs. 280 Profit =280 – 112 = Rs. 168 Profit percentage = (168/112) × 100 = 150%
If p3 + 9p2 + 8p + 13 = 6p2 + 5p + 12, then find the value of {(p4 + 1/p2)}/(p2 + 3p +...
√4096 + √(?) + 13 – 29 = 148
If (x2 + y2 + z2 - 4x + 6y + 13) = 0, then find the value of (x + y + z).
If P3 + 3P2 + 3P = 7, then the value of P2+ 2P is –
Find the values of 'a' and 'b', so that the polynomial x3 − ax2 − 13x + b has (x−1) and (x+3) as factors: