Question
A shopkeeper sold three types of items A, B and C. He
sold items A and B in the ratio of 16:21, while sold items C and A in the ratio of 5:8. The price of each item C is Rs. 16 and each item B is Rs. 9. The total revenue earned from selling all the item C is Rs. 145 less than the total revenue earned from selling all the items B. Find the number of items A sold by the shopkeeper.Solution
Let, number of item A and number of item B sold by shopkeeper be ‘16a’ and ‘21a, respectively. Number of item C sold by shopkeeper = (5/8) × 16a = 10a So, 21a × 9 – 10a × 16 = 145 189a – 160a = 145 29a = 145 a = 5 Number of item A sold by shopkeeper = 16a = 80
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