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Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 480) × 90% = Rs. 0.90x + 432 According to the question, 0.90x + 432 – 1.2x = 90 432 – 90 = 0.3x 0.3x = 342 x = 1140 Selling price of article ‘B’ = 0.90 × 1140 + 432 = Rs. 1458 Marked price of the article ‘B’ = 1458/90 × 100 = Rs. 1620
For a projectile, maximum range is obtained when angle of projection is:
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What is the focal length of a plane mirror?
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Decibel is used to measure the ___________.
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