Question
The cost price of article A and B is Rs. ‘X’
and Rs. (X + 480), respectively. Article A is sold at 20% profit while article B is sold at 10% loss. If selling price of article B is Rs. 90 more than that of article A and article B is sold after giving a discount of 10%, then find the marked price of article B.Solution
Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 480) × 90% = Rs. 0.90x + 432 According to the question, 0.90x + 432 – 1.2x = 90 432 – 90 = 0.3x 0.3x = 342 x = 1140 Selling price of article ‘B’ = 0.90 × 1140 + 432 = Rs. 1458 Marked price of the article ‘B’ = 1458/90 × 100 = Rs. 1620
Simplify:
(β3 + 1)/(β3 β 1) + (β3 β 1)/(β3 + 1)
(0.64)3/2 = ?
If β7 Γ β35 = xβ5, then find the value of x
Find the remainder when 798 is divided by 5.
If β35 = 5.9 find the value of β(5/7)
(1.69)Β -1.5Β = ?
If 2x = 3y = 6-z, then (1/x) + (1/y) + (1/z) =?
Simplify: (16)(3/4) Γ (8)(2/3)
Value of (x7/x6)6/5 is:
(3125)Β -3/5Β = ?