Question
The cost price of article A and B is Rs. ‘X’
and Rs. (X + 550), respectively. Article A is sold at 20% profit while article B is sold at 10% loss. If selling price of article B is Rs. 60 more than that of article A and article B is sold after giving a discount of 10%, then find the marked price of article B.Solution
Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 550) × 90% = Rs. 0.90x + 495 According to the question, 0.90x + 495 – 1.2x = 60 495 – 60 = 0.3x 0.3x = 435 x = 1450 Selling price of article ‘B’ = 0.90 × 1450 + 495 = Rs. 1800 Marked price of the article ‘B’ = 1800/90 × 100 = Rs. 2000
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1 Nibble is equal to
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 l _ _ m...
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SURPRISE: IRHVHFIK:: HESITATE: ?
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M _ N _ E...Select the option that is related to the fifth number in the same way as the second number is related to first number and the third number is related to...