Question
The cost price of article A and B is Rs. ‘X’
and Rs. (X + 550), respectively. Article A is sold at 20% profit while article B is sold at 10% loss. If selling price of article B is Rs. 60 more than that of article A and article B is sold after giving a discount of 10%, then find the marked price of article B.Solution
Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 550) × 90% = Rs. 0.90x + 495 According to the question, 0.90x + 495 – 1.2x = 60 495 – 60 = 0.3x 0.3x = 435 x = 1450 Selling price of article ‘B’ = 0.90 × 1450 + 495 = Rs. 1800 Marked price of the article ‘B’ = 1800/90 × 100 = Rs. 2000
(750 / 15 × 15 + 152 + 20% of 125) = ?3
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
104 × 21 ÷ 13 + ? % of 300 = 320 + 22
84% of 800 + 70% of 640 = 14 × ?
26% of 650 + 15% of 660 – 26% of 450 = ?
9/5 × 18/25 ÷ 42/21 = ? - 82/75
What will come in the place of question mark (?) in the given expression?
48 X 2.5 + 20% of 150 = ? + 166
18 × √225 + 378 ÷ √441 = ? × 9
3.2% of 500 × 2.4% of ? = 288
What will come in place of the question mark (?) in the following expression?
18 × 16 – 11 × 4 = 15² + ?
