Question
A shopkeeper marked an article 40% above its cost price
and made a profit of Rs. 80 when he sold the article after giving a discount of 25%. Find the profit percent earned by the shopkeeper if he had sold the article for Rs. 2016.Solution
Let cost price of the article is Rs. ‘x’ So, Selling price of the article = 0.75 × 1.4 × x = Rs. 1.05x According to question; ⇒ 1.05x – x = 80 ⇒ 0.05x = 80 ⇒ x = 1600 Desired Percentage = [(2016 – 1600)/1600] × 100 = 26%
(21% of 360) ÷ 0.8 =?
(γ(0.4)γ^(1/3)Β Γ γ(1/64)γ^(1/4)Β Γ γ16γ^(1/6)Β Γ γ(0.256)γ^(2/3))/(γ(0.16)γ^(2/3)Β Γ 4^(-1/2)Β Γγ1024γ^(-1/4) ) = ?
What will come in the place of question mark (?) in the given expression?
?2 = 3945 Γ· 5 + 774 Γ· 6 β 77Β
If 960 Γ· 16 + 875 Γ· 25 - x + 28 Γ 6 = 1350 Γ· 18 Γ 222 Γ· 37, then the value of x is:
(54/6) Γ 5 + 12 Γ (17/2) = ?% of 700
30% of 60% of 1800 + 13 Γ 14 = (? Γ· 75) Γ 5
45% of 1020 + ?% of 960 = 747
120% of 400 + ?% of 520 = 1000
(16% of 550 β 22% of 700 + 45% of 800) = ?
300% of (3341 – 471) = ? × (√4225/195)
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