Question
A bag contains 10 red books, 7 yellow
>books and 7 green books . 3 books are drawn randomly. What is the probability that the books drawn is not a green book ?Solution
Total number of books = 10 + 7 + 7 = 24 Let S be the sample space. Then, n(S) = number of ways of drawing 3 books out of 24 = 24C3 = `(24 xx 23 xx 22)/ (3 xx 2 xx 1)` = 3036 Let E= event of drawing no green books n(E) = 17C3 = `(17 xx 16 xx 15)/(3 xx 2 xx 1)` = 680 `:.` P(E) = `(n(E))/(n(S))` = `680/3036` = `170/759`
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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