Question
A person starts from a point P and travels 5 km
eastwards to Q and then turns left and travels thrice that distance to reach R. He again turns left and travels five times the distance he covered between P and Q and reaches his destination S. The shortest distance between the starting point and the destination is ÂSolution
Draw PT ⊥ RS Then, RT = PQ = 5 km PT = QR = 15 km ST = (RS – RT) = (25 – 5) km = 20 km In ∆PTS, PS = √ PT² + ST² =  √ 15² + 20² = √225 + 400 = √625 = 25 Km
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