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    Question

    A box holds 8 green balls, 7 blue balls, and 5 yellow

    balls. Three balls are picked randomly. What is the probability that at least two balls are blue?
    A 13/33 Correct Answer Incorrect Answer
    B 29/57 Correct Answer Incorrect Answer
    C 29/17 Correct Answer Incorrect Answer
    D 17/33 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Required probability = (Two blue balls and one either green or yellow) + (Three blue balls) = 3 × [(7/20) × (6/19) × (13/18)] + (7/20) × (6/19) × (5/18) = (3276/6840) + (210/6840) = (3486/6840) = 29/57

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