Question
A box holds 8 green balls, 7 blue balls, and 5 yellow
balls. Three balls are picked randomly. What is the probability that at least two balls are blue?Solution
ATQ,
Required probability = (Two blue balls and one either green or yellow) + (Three blue balls) = 3 × [(7/20) × (6/19) × (13/18)] + (7/20) × (6/19) × (5/18) = (3276/6840) + (210/6840) = (3486/6840) = 29/57
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