Question
Two playing cards are drawn one after another without
putting the first one back. What is the probability that at least one of them is an Ace?Solution
ATQ,
= Probability that both cards are aces + Probability that first card is ace × second is not ace + Probability that first is not ace × second is ace
= (4/52) × (3/51) + (4/52) × (48/51) + (48/52) × (4/51)
= (12 + 192 + 192) ÷ (52 × 51)
= 396 ÷ 2652
= 33/221
Statement: A = B ≥ C ≥ D < E < F ≥ G; D > H
Conclusion:
I.  H ≥ G
II. Â A > H
...Statements: A > B > C, C < D > E, E = F > G
Conclusion:
I. C = G
II. A > F
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is/are definitely true and then...
Statements:
O ≤ P = Y ≤ U; L > G ≥ W = Q ≥ Y; G < A ≤ R < D
Conclusions:
I. P < R
II. G ≥ P
Statements: N < G ≥ F > E ≥ D, D = O ≥ I > P
Conclusions:
I. D < G
II. N > I
III. P < E
Statements: P = Q = R > S > T > Z; U > R < V < W > X
Conclusions:
I. W > Z
II. R < W
III. R < X
Statements: N = Q < X ≤ L, L > T = G ≥ E
Conclusions:
I. L ≥ Q
II. G > X
III. L > N
Statements: W ≤ T = R; T < U < S; X = W ≥ Y
Conclusions:
I. S > Y
II. W ≥ S
III. U ≥ Y
Statements: L ≤ Y = T ≤ S; S = F ≤ U; K > N = U
Conclusions:
I. K > T
II. U ≥ L
...Statements: J > K = L ≥ N > M > O ≥ P
Conclusions:
I. K ≥ O
II. J = N
III. P < N