Question
Two playing cards are drawn one after another without
putting the first one back. What is the probability that at least one of them is an Ace?Solution
ATQ,
= Probability that both cards are aces + Probability that first card is ace × second is not ace + Probability that first is not ace × second is ace
= (4/52) × (3/51) + (4/52) × (48/51) + (48/52) × (4/51)
= (12 + 192 + 192) ÷ (52 × 51)
= 396 ÷ 2652
= 33/221
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