Question
In a container holding 18 balls of three shades –
orange, purple, and white – the probability of picking an orange ball is 1/3. If the count of white balls is twice the number of purple balls, determine the probability of selecting a purple ball.Solution
ATQ,
Let the number of orange balls be x. So, x/18 = 1/3 x = 6 Let the number of purple balls be y. Then, white balls = 2y Now, y + 2y = 18 – 6 3y = 12 y = 4 Required probability = 4/18 = 2/9
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