Question
"A box contains 54 rubber bands
in three colors: Red, Green, and Yellow. The probability of picking a green rubber band is (1/3), and the number of yellow rubber bands is twice the number of red rubber bands. What is the probability of picking a yellow rubber band from the box?"Solution
ATQ, Number of green bands in the box = 54 × (1/3) = 18 Remaining bands = 54 – 18 = 36 Let, number of yellow bands and red bands be 2b and b, respectively, Therefore, 2b + b = 36 3b = 36 b = 36/3 = 12 So, number of yellow bands = 2 × 12 = 24 Therefore, required probability = (24/54) = 4/9
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
