The profit from sales, amounting to Rs. 4,200, is distributed between two salesmen, 'Amit' and 'Bheem,' in such a way that 'Amit' receives more money than 'Bheem.' What is the probability that the amount received by 'Amit' is more than twice as much as 'Bheem,' ensuring that the amounts received by both 'Amit' and 'Bheem' are integral values?
ATQ, Let the share of 'Bheem' be Rs. 'b' So, share of 'Amit' = Rs. (4200 - b) So, 4200 - b > 2b Or, 4200 > 3b So, 1400 > b Here, 'b' can take 1400 values i.e. from 0 to 1399. Now, since it is given that 'Amit' received more money than 'Bheem'. b < 4200 ÷ 2 Or, b < 2100 Here 'b' can take 2100 value i.e. from 0 to 2099. So, required probability = (1400/2100) = (2/3)
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