Question
A is trying to break a bulb by throwing balls at it. If
he hits the bulb 4 times in every 11 throws and bulb breaks 3 times out of 7 hits, then find the probability of A breaking the bulb.Solution
Probability of A hitting the bulb = 4/11 Probability of the bulb being broke on getting hit = 3/7 Probability of A breaking the bulb = (4/11) × (3/7) = 12/77
More Probability Questions
If (7a + b) : (7a - b) = 7:3, then find the value of a:b?
2(3/4) of 2880 + 54% of 7520 - ? = 302
√10201 × √3969 - (52)² = √? + (60)²
...- What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 ‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...
5 + 2 × 3 ÷ (3 × 2) ÷ 4
Simplify the given expression.
(1/4) of {6 4 - 28 × 15 + 13 × 16 - 12.5 of 12 2 }
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
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