Question
A box contains 8 red, 5 green, and 7 blue balls. Two
balls are drawn at random without replacement. What is the probability that both balls drawn are of different colors?Solution
Total number of balls = 8 + 5 + 7 = 20. The total number of ways to choose 2 balls from 20 is: C(20, 2) = (20 × 19) / 2 = 190. Now, the number of ways to choose 2 balls of different colors: Red and Green: 8 × 5 = 40 Red and Blue: 8 × 7 = 56 Green and Blue: 5 × 7 = 35 So, the total number of ways to choose 2 balls of different colors = 40 + 56 + 35 = 131. Therefore, the probability is: P(different colors) = 131 / 190 Correct Option: a)Â
Which of the following cases does not explain the maxim ‘Damnum Sine Injuria’?
How are the assets of any insurer in India be kept as per the Insurance Act, 1938?
Property is designated as "Stolen property".
The Rent controller shall be not below the rank of:Â
In how many cases the right of private defence of the body extends to causing death?
What is the word for "a person who is always optimistic and sees the good in everything"?Â
A small company is a company whose paid-up capital and turn over shall________________
Who forms the committee responsible for recommending the appointment of the State Chief Information Commissioner and the State Information Commissioners...
For the liability of the master to arise in the context of vicarious liability, which of the following is NOT one of the essentials?
Impleading an unncessary party to a suit is___
Relevant for Exams:
