Question
A box contains 8 red, 5 green, and 7 blue balls. Two
balls are drawn at random without replacement. What is the probability that both balls drawn are of different colors?Solution
Total number of balls = 8 + 5 + 7 = 20. The total number of ways to choose 2 balls from 20 is: C(20, 2) = (20 × 19) / 2 = 190. Now, the number of ways to choose 2 balls of different colors: Red and Green: 8 × 5 = 40 Red and Blue: 8 × 7 = 56 Green and Blue: 5 × 7 = 35 So, the total number of ways to choose 2 balls of different colors = 40 + 56 + 35 = 131. Therefore, the probability is: P(different colors) = 131 / 190 Correct Option: a)Â
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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