Question
Ten tickets numbered 1 to 15 are placed in a box, mixed
up thoroughly and then one ticket is drawn randomly. If it is known that the number on the drawn ticket is more than 3, what is the probability that it is an even number?Solution
Let A be the event ‘the number on the ticket drawn is even’ and B be the event ‘the number on the ticket drawn is greater than 3’. We have to find P(A|B). Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15} Then A = {2, 4, 6, 8, 10, 12, 14}, B = {4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15} and A ∩ B = {4, 6, 8, 10, 12, 14} Also P(A) = 7/15, P(B) = 12/15 and P(A ∩ B) = 6/15 Then P(A|B) = P(A ∩ B)/P(B) = (6/15)/(12/15) = 1/2
9999² + 1111² =?
What will come in the place of question mark (?) in the given expression?
(5/8) × 1600 + (2400 ÷ 25) = ?
What will come in the place of question mark (?) in the given expression?
40% of 150 - ?% of 75 = 15 × 1.6
9 × 4 ? ÷ 16 = 144
The value of 5³ × 5⁴ × 5² = ?
- What will come in place of (?) in the given expression.
(84 + 36 ÷ 6) × 2 = ? What value should come in place of the question mark (?) in the following question?
15 × 19 – 13 × 5 = 122 ...
18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
Simplify the following expressions and choose the correct option.
{(4/9 of 567) + √1936} ÷ 8 = ?
5/13 × 104 + 1(2/9) × 198 = 133 + ?
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