Given that E and F are events such that P(E) = 0.8, P(F) = 0.4 and P(E∩ F) = 0.2. Find P(F|E).
Given P (E) = 0.8, P (F) = 0.4 and P (E ∩ F) = 0.2 We know that by the definition of conditional probability, P(A/B) = P(A ∩ B)/P(B) By substituting the values, we get = P(E|F) = P(E ∩ F)/P(F) = 0.2/0.4 = 2/4 = 1/2 And = P(F|E) = P(E ∩ F)/P(E) = 0.2/0.8 = 2/8 = 1/4
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Some pillars are buildings.
All buildings are flats.
No flat is a house.
Conclusion:...
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Mostly Maruti is Audi.
A few Audi is BMW.
All BMW are roofs.
No Toyota is Honda.
Conclusion: ...
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Some tables are chairs.
No chair is a book.
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Statement :
All balls are pencils.
All keys are balls.
Conclusion:
I. At least some pencils are keys.
II. All pencils are balls.
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Some hangers are cloths.
All cloths are drawers.
Some drawers are almirahs.
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I . Some ...
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No notebooks is a pages.
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Few M are not N.
All N are O.
Only m few O are P.
Conclusion:
1. All M can be N.
2. Some M a...
Statements:
Some heights are weight.
Some weight are tall.
Some tall are short.
Conclusions:
I. No height is tall.
II. Some heights are tall.
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