Question
The probability of selecting a rotten apple randomly
from a heap of 600 apples is 0.14. What is the number of rotten apples in the heap?Solution
Total number of apples in the heap = n(S) = 600 Let E be the event of selecting a rotten apple from the heap. Number of outcomes favourable to E = n(E) P(E) = n(E)/n(S) 0.14 = n(E)/600 ⇒ n(E) = 600 × 0.14 ⇒ n(E) = 84 Therefore, the number of rotten apples in the heap = 84
More Probability Questions
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
33.33% of 809.891 + 66.66% of 212.91 = ?
(?)2 = (5.99)2 + (7.88)2 + 43.99
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
124.88% of 1199.85 + 99.99 ÷ 3.99 = ?
(519.98 + ?) ÷ 13.01 = √440 + 20.0
(439.98 ÷ 10.99) × 23.98= ? × (23.98) 2 ÷ 47.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
?² x
