Question
If four hats are picked at random, what is the
probability that one is green, two are blue and one is red? A box contains 6 red, 4 blue, 2 green and 4 yellow hats.Solution
Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 4 hats out of 16 = ¹⁶C_4 = (16 × 15× 14 × 13 )/( 4 × 3 × 2 × 1) = 1820 Let E= event of drawing 4 hats so that one is green, two are blue and one is red = n(E) = ²C_1×⁴C_2×⁶C_1= 2 × 6 × 6= 72 ∴ P (E) = (n(E))/(n(S))= 72/1820 = 18/455
What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
143 119 107 101 98 ?
96 89 ? 90 94 91
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19, 235, 260, 324, 333, ?
What will come in place of the question mark (?) in the following series?
305...
In each of the following number series, one term is missing. Find the missing term.
3, 5, 20, 24, 144, 150, ?
1029, 1030, 1039, 1064, ?, 1194
75, 80, 95, ?, 155, 200
What will come in place of the question mark (?) in the following series?
1515, 184, ?, 455, 967, 624
7 29 61 ? 211 349
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