Question
A man goes to Ahmedabad from Kolkata at a speed of
78km/hr and returns to Kolkata at speed of 91km/hr, through same route. What is his average speed (in km/hr) of the entire journey?Solution
For equal distances, Average speed = (2 × Speed₁ × Speed₂) ÷ (Speed₁ + Speed₂) = (2 × 78 × 91) ÷ (78 + 91) = (2 × 7098) ÷ 169 = 14196 ÷ 169 = 84 km/hr
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