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    Question

    A can do a piece of work in 32 days and B in 48 days.

    They work together for 8 days and then A goes away. In how much time (in days) will B finish the 60% of the remaining work?
    A 18(2/3) Correct Answer Incorrect Answer
    B 19(3/4) Correct Answer Incorrect Answer
    C 16(4/5) Correct Answer Incorrect Answer
    D 17(3/7) Correct Answer Incorrect Answer

    Solution

    AтАЩs 1 day work = 1/32 BтАЩs 1 day work = 1/48 Together 1 day work = 1/32 + 1/48 = (3 + 2) / 96 = 5/96 Work done in 8 days = 8 ├Ч 5/96 = 40/96 = 5/12 Remaining work = 1 тИТ 5/12 = 7/12 60% of remaining work = 60% of 7/12 = (60/100) ├Ч 7/12 = 7/20 Now B works alone. Time taken by B = (7/20) ├╖ (1/48) = (7/20) ├Ч 48 = 84/5 = 16(4/5)

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