Question
The least number of square tiles required to pave the
ceiling of a room 525 centimetre long and 378 centimetre broad is:Solution
Given: Length = 525 cm Breadth = 378 cm We need square tiles of the largest size to exactly cover the area ⇒ Find HCF of 525 and 378 Find HCF of 525 and 378 525 = 3 × 5 × 5 × 7 378 = 2 × 3 × 3 × 3 × 7 Common factors = 3 and 7 ⇒ HCF = 21 cm Area of ceiling = 525 × 378 = 198,450 cm² Area of one tile = 21 × 21 = 441 cm² Required tiles = 198,450 ÷ 441 = 450
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