Question
A thief is noticed by a policeman from a distance of 200
m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km/h and 11 km/h, respectively. What is the distance (in metres) between them after 9 minutes?Solution
Initial distance = 200 m
Speed of thief = 10 km/h =166.67\frac{10000}{60} = 166.67 m/min
Speed of policeman = 11 km/h =Β 183.33\frac{11000}{60} = 183.33 m/min
Relative speed = 183.33 β 166.67 = 16.66 m/min Distance closed in 9 minutes = 9 Γ 16.66 = 150 m Distance between them after 9 minutes = 200 β 150 = 50 metres
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