Question
Eight years ago, a man's mother was three times the age
of her son. After eight years, the mother's age will be twice the age of her son. What is the ratio of their present ages?Solution
The correct answer is A
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf 9x2 + 16y2 = 24xy, then find the ratio of ‘x’ and ‘y’, respectively.
- Suppose [a + (1/16a)] = 3, then the value of [16a³ + (1/256a³)] is:
If, 6x + y = 20, and 2xy = 32, and 6x > y, then find the value of 216x³ – y³.
If x + 1/x = 2, find x⁷ + 1/x⁷.
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
Three cubes of metal whose edges are 3cm, 4cm and 5cm. respectively are melted and a single cube is formed. What is the length of the edge of the newly ...
A number is increased by 20%, and the resulting number is decreased by 20%. If the initial number is ₹x, the final number is ₹2880. What is the valu...