Question
A milk vendor has 2 vessels of milk and water. The first
contains 80% milk and the rest is water. The second contains 50% milk. How much mixture (in L) should he mix from each of the vessels so as to get 9 litres of mixture such that the ratio of water to milk is 1 : 2? (Write your answer in the order of vessel 1 and vessel 2)Solution
Given- Vessel 1= 80% milk, 20% water. Vessel 2=50% milk, 50% water. Desired mixture= 9 liters with water ratio of 1:2  Let x = liters from Vessel 1  and 9- x = liters from Vessel 2. Total water= 0.2x +0.5(9-x) Total milk= 0.8x +0.5(9-x) Ratio= 0.2x+0.5(9-x)/ 0.8x+0.5(9-x) = 1/2 0.2x + 4.5- 0.5x = ½ × (0.8x+4.5+0.5x) 4.5-0.3x =0.15x + 2.25 0.45x =2.25 x=2.25/0.45 x=5 In vessel 1 = 5 In vessel 2 =9-5=4.
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