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    Question

    The ratio of arms to a quadrangle is 2: 3: 4: 5, and the

    perimeter is 1050 cm. Find the length of the smallest arm (in cm).
    A 145 Correct Answer Incorrect Answer
    B 150 Correct Answer Incorrect Answer
    C 155 Correct Answer Incorrect Answer
    D 160 Correct Answer Incorrect Answer

    Solution

    ATQ, Let the lengths of the arms be 2x, 3x, 4x, and 5x. The sum of the arms (perimeter) is 2x+3x+4x+5x=1050. Simplify: 14x=1050. Solve for x:x =1050/14=75. The smallest arm is 2x=2×75=150. So, the length of the smallest arm is 150 cm.

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