Question
The ratio of arms to a quadrangle is 2: 3: 4: 5, and the
perimeter is 1050 cm. Find the length of the smallest arm (in cm).Solution
ATQ, Let the lengths of the arms be 2x, 3x, 4x, and 5x. The sum of the arms (perimeter) is 2x+3x+4x+5x=1050. Simplify: 14x=1050. Solve for x:x =1050/14=75. The smallest arm is 2x=2×75=150. So, the length of the smallest arm is 150 cm.
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