If the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 24
m. then find the area of the triangle.

Given that the sides of the triangle are in the ratio 3: 4: 5, let's denote the sides as 3x , 4x , and 5x . The perimeter of the triangle is given as 24 meters. ATQ- 3x+4x+5x =24 12x =24 X=2 Now sides =6,8 and 10. Since the sides are in the ratio 3:4:5, this is a right-angled triangle (Pythagorean triplet). The sides 6 meters and 8 meters are the legs, and 10 meters is the hypotenuse. Area of a right-angled triangle- Area =1/2 ×base ×height. =1/2 ×6×8 =24m ²