Question
A person reaches the college with a speed of 45 km / hr
from the hostel till 5 minutes late. If he runs a bike at 60 kmph and he reaches 4 minutes early. Find the distance between the hostel and the college.Solution
Let us consider the time of the journey be t hrs., As we know, the distance is the same. According to the question 45 (t + 5/60) = 60 (t-4/60)  3 (t + 5/60) = 4 (t-4/60) 3t + 15/60 = 4t-16/60  4t-3t=15/60 + 16/60 t = 31/60 Distance = speed x time Distance = 45 × (31/60 + 5/60) = 45 x 36/60 = 27 km
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