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Let the speed of the Tellyn be 11 units. Speed of the Tellyn after decrement = 11 x 10/11 = 10 units Speed ratio = 11:10 Time ratio = 10:11 ATQ- 11-10=1 unit 1 unit =13 min 10 unit = 10 x 13=130 min Total time taken by Tellyn in the starting was 130 min.
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
25.04 × 22.03 + 383.92 ÷ ? + 23.78% of 1499.98 = 926.08
{(84.04% of 649.95 + 27.92 × 13.13) – 21.11 × ?} = 763.35
136.02 + 80.004 - 9.892 + {(30.02)2 /(15.02 × 1.98)} of 18.22% = ?
(899.117 + 1.1121) X 72.731 = ? + 49.95 X 64.78 + 29.50
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
? = 685.24 + 1024.97 – 9.992
(?)2 + 4.113 = 25.92 – 32.03