Question
The tellyn moves at a speed of normal speed (10/11) and
takes 13 minutes more than normal time. Find the usual time taken.Solution
Let the speed of the Tellyn be 11 units. Speed of the Tellyn after decrement = 11 x 10/11 = 10 units Speed ratio = 11:10 Time ratio = 10:11 ATQ- 11-10=1 unit 1 unit =13 min 10 unit = 10 x 13=130 min  Total time taken by Tellyn in the starting was 130 min.
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What is the system software?
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