Question
The average of the first eight multiples of 6
is:Solution
Since, the first 8 multiple of 6 are 6, 12, 18, 24, 30, 36, 42, 48 = The average of all 8 numbers = (6 + 12 + 18 + 24 +30+36 + 42 + 48)/8 The required average = 216/8 = 27
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