Sudarsan and Abraham appear for an interview for two vacancies. The probability of Sudarsan's selection is 1/3 and that of Abraham's selection is 1/5. Find the probability that none of them be selected.

Given: Sudarshan and Abraham appear for an interview for two posts such that the probability of Sudarshan's selection is 1/3 and that of Abraham's selection is 1/5. Let E = event that Sudarshan is selected Let F = event that Abraham is selected   P(E) = 1/3 and P(F) = 1/ 5 As we know that, if P(A) = x then P(A) = 1 - x P(E’) = 1-(1/3) =2/3   and P(F’) = 1-(1/5) =4/5                                                               P(event that none of them is selected)=2/3 ×4/5 =8/15