Question
The age of the father 10 years ago was thrice the age of
his son. Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?Solution
Let the ages of father and son 10 years ago be 3x and x years respectively. Then, (3x + 10) + 10 = 2[(x + 10) + 10] 3x + 20 = 2x + 40 X = 20 Â Required ratio = (3x+10): (x + 10) = 70:30 = 7:3
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