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    Question

    The age of the father 10 years ago was thrice the age of

    his son. Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
    A 3 : 2 Correct Answer Incorrect Answer
    B 7 : 3 Correct Answer Incorrect Answer
    C 5 : 3 Correct Answer Incorrect Answer
    D 5 : 2 Correct Answer Incorrect Answer

    Solution

    Let the ages of father and son 10 years ago be 3x and x years respectively. Then, (3x + 10) + 10 = 2[(x + 10) + 10] 3x + 20 = 2x + 40 X = 20   Required ratio = (3x+10): (x + 10) = 70:30 = 7:3

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