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      Question

      The area of a square is 81x┬▓+72x+16. Find the measure

      of each side of the square, where x > 0.
      A 1 Correct Answer Incorrect Answer
      B 2 Correct Answer Incorrect Answer
      C 3 Correct Answer Incorrect Answer
      D 4 Correct Answer Incorrect Answer

      Solution

      The area of a square = 81x┬▓ + 72x + 16 ┬а = (9x) ┬▓ + 2 x 9x x 4 + (4)2 ┬а = (9x + 4)2 Now, ┬а a┬▓ = (9x + 4)2 a=9x + 4 Taking 2 as common, we get. =2(9x/2 + 2) ┬а The required value is 2(9x/2 + 2)

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