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    Question

    The area of a square is 81x²+72x+16. Find the measure

    of each side of the square, where x > 0.
    A 1 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 3 Correct Answer Incorrect Answer
    D 4 Correct Answer Incorrect Answer

    Solution

    The area of a square = 81x² + 72x + 16   = (9x) ² + 2 x 9x x 4 + (4)2   = (9x + 4)2 Now,   a² = (9x + 4)2 a=9x + 4 Taking 2 as common, we get. =2(9x/2 + 2)   The required value is 2(9x/2 + 2)

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