Question
The area of a square is 81x²+72x+16. Find the measure
of each side of the square, where x > 0.Solution
The area of a square = 81x² + 72x + 16  = (9x) ² + 2 x 9x x 4 + (4)2  = (9x + 4)2 Now,  a² = (9x + 4)2 a=9x + 4 Taking 2 as common, we get. =2(9x/2 + 2)  The required value is 2(9x/2 + 2)
More Previous year papers Questions
?% of 1200.22 + 319.82 = 3.99 × 295.64
?% of (140.31 ÷ 19.97 × 80.011) = 139.98
30.05% of 149.97 + ? X 8.88 = (39.95 + 12.012 - 13.0322)2Â
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
(8000)1/3  × 10.11 × 8.97 ÷ 18.32 = ? + 25.022
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
(? + 11.86) X 14.89 = 19.89% of 2399.89
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 499.87 – 24.95 × 14.04 + (20.15)²
(32.25 × 14.98) + 31.76% of 1499.89 = ? × 3.67
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