Question
The area of a square is 81x²+72x+16. Find the measure
of each side of the square, where x > 0.Solution
The area of a square = 81x² + 72x + 16  = (9x) ² + 2 x 9x x 4 + (4)2  = (9x + 4)2 Now,  a² = (9x + 4)2 a=9x + 4 Taking 2 as common, we get. =2(9x/2 + 2)  The required value is 2(9x/2 + 2)
Pusa Deepali is a variety of:
Capitate type of antenna are found in _____
Bud scales (cataphylls) are_____ designed for protecting buds (apical or axillary).
Part of the cell wall of endodermal cells prevents water from moving into the cell is calledÂ
Eugenol is the important chemical content of:
The typical pH value of the midgut in most insects is closest to which of the following values?
Microorganisms used for suppression of plant diseases are called as ____
Judicious removal of plant part to obtain better and qualitative yield is termed asÂ
Chlorophyll is the major pigment present in leaves ,Which element is known as a ‘constituent of chlorophyll’?
Out of the following quantity, which is required to irrigate 1.0 ha land area with 50mm depth of irrigation?
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