Question
The HCF of 1683, 2244 and 5049 is x. The sum of digits
of x isSolution
1683 = 3 x 3 x 11 x 17 2244 = 2 x 2 x 3 x 11 x 17 5049 =3 x 3 x 3 x 11 x 17 The HCF = (3 x 11 x 17) =561 So, x = 561 Now, The sum of digits of x = (5 + 6 + 1)=12 .. The required sum of digits of x is 12
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