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    Question

    The HCF of 1683, 2244 and 5049 is x. The sum of digits

    of x is
    A 15 Correct Answer Incorrect Answer
    B 11 Correct Answer Incorrect Answer
    C 13 Correct Answer Incorrect Answer
    D 12 Correct Answer Incorrect Answer

    Solution

    1683 = 3 x 3 x 11 x 17 2244 = 2 x 2 x 3 x 11 x 17 5049 =3 x 3 x 3 x 11 x 17 The HCF = (3 x 11 x 17) =561 So, x = 561 Now, The sum of digits of x = (5 + 6 + 1)=12 .. The required sum of digits of x is 12

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