Question
The average of 30 numbers is 55. The average of the
first 15 numbers is 51 and the average of the last 12 numbers is 56. What is the average of 68, 74 and the remaining 3 numbers?Solution
Sum of all 30 terms = 30 x 55= 1650 Sum of first 15 terms = 15× 51 = 765 Sum of last 12 terms = 12 x 56 = 672 After removing the first 15 and last 12 terms, there will be 3 terms remaining. Sum of remaining 3 terms = 1650 (765 +672) = 213 According to the question, 68 and 74 are added to the sum of 3 terms. Thus, the number of total terms becomes 5. Average of 5 terms = (213 +68 + 74)/5 = 71 71 is the average of 68, 74 and the remaining 3 numbers.
A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1525.5 and simple interest of Rs.1500 at the end of 2 ye...
Naina lent Rs. 9,800 to Mohini for 4 years and Rs. 8,800 to Mitali for 6 years on simple interest at the same rate of interest and received Rs. 11,040 i...
A person invested a sum of Rs. 9000 at r% per annum at simple interest and a sum of Rs. 13500 at (r-4)% at simple interest. If total interest earned on ...
A sum of money doubles itself in 5 years in how many years it will be 3 times?
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 4 years and 6 years ?
Find the total amount returned by Manish to the bank at the end of three years, when Rs.24000 is borrowed at the rate of (25/2)% compounded annually?(ca...
Simica invested a certain amount of money at a simple interest rate of 12.5% per annum and earned Rs. 2,400 as interest over 3 years. If Tabu invested t...
A sum of money lent at 5% rate of simple interest. The difference between interest for 6 years and 4 years is Rs. 2000. Find the principal amount.
An initial principal sum of Rs. 8000, invested by Pranav, accrued interest at a compound rate of 20% annually for a period of 2 years. Subsequently, the...
If Rs. 15000 is invested at 14% per annum, compounded yearly, calculate the interest earned in one year.