Question
Solution
1-tan2 
=1/2 tan²  = 1/2 1 + tan²  = 3/2  sec2  = 3/2 .           (1)  cos2  = 2/3 1-cos2  = 1/3  sin2  = 1/3  cosec2  = 3            . (2) Hence (1) + (2), (cosec² + sec² )=3+3/2 =9/2 .. The required value is 9/2.
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