Question
From a watch tower of 200 m height, the angles of
depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.Solution
In triangle ABC- Tan45 =200/AC AC =200m Now – Tan30 =200/AD 1/√3 =200/AD AD=200√3. Distance between the cliffs = AD=AC+CD 200√3 =200+CD CD=200√3-200 =200(√3-1) m 
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