Question
If tan θ = 1 (θ an acute angle) then the value of 2
sin θ cos θ – cosec²θ is:Solution
tan θ = 1 =tan45 θ=45. Then – 2 sin θ cos θ – cosec²θ. 2 sin45.cos45-cosec2 45 2× (1/√2 ×1/√2) – (√2)2 =2×1/2 -2 =1-2= -1
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