Question
In a trapezium ABCD, sides AD and BC are parallel to each other with a perpendicular distance of 8 meters between them. The lengths of AD and BC are both 10 meters, and the length of side DC is 15 meters. If AB is longer than DC, find the perimeter (in meters) of trapezium ABCD.
Given – DE=CF=8cm DC=EF=15 AD=BC=10 By Pythagoras theorem- AE=FB=6 So, AB=6+15+6=27cm So now perimeter of ABCD=AD+DC+CB+AB =10+15+10+27=62cmMore Previous year papers Questions
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