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    Question

    In a trapezium ABCD, sides AD and

    BC are parallel to each other with a perpendicular distance of 8 meters between them. The lengths of AD and BC are both 10 meters, and the length of side DC is 15 meters. If AB is longer than DC, find the perimeter (in meters) of trapezium ABCD.
    A 25cm Correct Answer Incorrect Answer
    B 42cm Correct Answer Incorrect Answer
    C 62cm Correct Answer Incorrect Answer
    D 18cm Correct Answer Incorrect Answer

    Solution

    Given – DE=CF=8cm DC=EF=15 AD=BC=10 By Pythagoras theorem- AE=FB=6 So, AB=6+15+6=27cm So now perimeter of ABCD=AD+DC+CB+AB =10+15+10+27=62cm

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