Question
In a trapezium ABCD, sides AD and
BC are parallel to each other with a perpendicular distance of 8 meters between them. The lengths of AD and BC are both 10 meters, and the length of side DC is 15 meters. If AB is longer than DC, find the perimeter (in meters) of trapezium ABCD.Solution
Given – DE=CF=8cm DC=EF=15 AD=BC=10 By Pythagoras theorem- AE=FB=6 So, AB=6+15+6=27cm So now perimeter of ABCD=AD+DC+CB+AB =10+15+10+27=62cm
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