Question
Two pillars of equal height stand on either side of a
roadway which is 150 m wide. At a point in the road between pillars, the elevations of the pillars are x° and y° so that tan then the height of each pillar is:Solution
Tan x ° =2/5, tan y°=3/5 Same height of pillars = h= 6=? Distance between pillar A and B= 15+10=25 ATQ given- 25=150 1 = 6 m Then height = 6 ×6 =36m
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