Question
The average age of A, B and C is 20 years. Two years ago
the sum of the ages of A and B was 6 more than that of C. Find the present age of C.Solution
A+B+C = 20×3=60 2years before = A+B+C = 60-6 =54 SO NOW ATQ- (A+B)+C=54 C+6+C = 54 2C =48 C= 24 SO now present age of C = 24+2=26 years
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