Question
A and B can complete a job together in 12.5 days; B and
C can complete the same job together in 18.75 days, while C and A can complete the same job together in 15 days. In how many days will A, B and C together be able to complete the same job alongside D, who is only 40% as efficient as C?Solution
A+B= 12.5 = 25/2days B+C=18.75=75/2days C+A=15days LCM of 25/2,75/2 and 15 = 150
Total 2(A+B+C)= 12+8+10=30 A+B+C =15 C = 15-12=3 D= 3×40/100=1.2 NOW A+B+C+D = 15+1.2=16.2 SO total days = 150/16.2 =1500/162=250/27
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?