Question

    The batting average for 50 innings of a cricket player

    is 60 runsHis highest score exceeds his lowest score by 118 runsIf these two innings are excludedthe average of the remaining 48 innings is 60 Find the highest score
    A 118 runs Correct Answer Incorrect Answer
    B 122 runs Correct Answer Incorrect Answer
    C 115 runs Correct Answer Incorrect Answer
    D 119 runs Correct Answer Incorrect Answer

    Solution

    ATQ, Average run for 50 inning of a cricket player = 60 Sum of run for 50 innings of a cricket player = 60 × 50 = 3000 Average run for 48 inning of a cricket player = 60 Sum of run for 48 innings of a cricket player = 48 × 60 = 2880 Sum of remaining 2 innings = 3000 - 1824 = 120 Let the minimum score be x and maximum score be x + 118 According to the question ⇒ x + x + 118 = 120 ⇒ 2x = 120 - 118 ⇒ 2x = 2 ⇒ x = 2/2 ⇒ x = 1 ∴ Maximum score = 1 + 118 = 119 runs

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