The batting average for 50 innings of a cricket player

Solution

ATQ, Average run for 50 inning of a cricket player = 60 Sum of run for 50 innings of a cricket player = 60 × 50 = 3000 Average run for 48 inning of a cricket player = 60 Sum of run for 48 innings of a cricket player = 48 × 60 = 2880 Sum of remaining 2 innings = 3000 - 1824 = 120 Let the minimum score be x and maximum score be x + 118 According to the question ⇒ x + x + 118 = 120 ⇒ 2x = 120 - 118 ⇒ 2x = 2 ⇒ x = 2/2 ⇒ x = 1 ∴ Maximum score = 1 + 118 = 119 runs