The batting average for 50 innings of a cricket player is 60 runsHis highest score exceeds his lowest score by 118 runsIf these two innings are excludedthe average of the remaining 48 innings is 60 Find the highest score

Solution

ATQ, Average run for 50 inning of a cricket player = 60 Sum of run for 50 innings of a cricket player = 60 × 50 = 3000 Average run for 48 inning of a cricket player = 60 Sum of run for 48 innings of a cricket player = 48 × 60 = 2880 Sum of remaining 2 innings = 3000 - 1824 = 120 Let the minimum score be x and maximum score be x + 118 According to the question ⇒ x + x + 118 = 120 ⇒ 2x = 120 - 118 ⇒ 2x = 2 ⇒ x = 2/2 ⇒ x = 1 ∴ Maximum score = 1 + 118 = 119 runs